Filling in Pascal's Triangle

• To fill in the values follow the following two steps:
  1. Set a value in column $h_0$ to twice the value of $h_1$ from the previous row.
  2. Add two adjacent numbers in the same row and place the sum below the space between them, on the next row.

  
  

  DIV		$h_0$	$h_1$	$h_2$	$h_3$	$h_4$	$h_5$	$h_6$	$h_7$	$h_8$	$h_9$	$h_{10}$	$h_{11}$
  	$x^0$	1
  	$x^1$		1
  	$x^2$	2		1
  	$x^3$		3		1
  	$x^4$			4		1
  	$x^5$				5		1
  	$x^6$					6		1
  	$x^7$						7		1
  	$x^8$							8		1
  	$x^9$								9		1
  	$x^{10}$									10		1
  	$x^{11}$										11		1

  
  

• Continue these two steps, first by filling in the next value for $h_0$, and then taking the adjacent sum.

• Finally, to obtain the divider DIV, multiply the value of DIV from the previous row by 2, starting in row $x^0$ with 0.5.

  
  

  DIV		$h_0$	$h_1$	$h_2$	$h_3$	$h_4$	$h_5$	$h_6$	$h_7$	$h_8$	$h_9$	$h_{10}$	$h_{11}$
  0.5	$x^0$	1
  1	$x^1$	0	1
  2	$x^2$	2	0	1
  4	$x^3$	0	3	0	1
  8	$x^4$	6	0	4	0	1
  16	$x^5$	0	10	0	5	0	1
  32	$x^6$	20	0	15	0	6	0	1
  64	$x^7$	0	35	0	21	0	7	0	1
  128	$x^8$	70	0	56	0	28	0	8	0	1
  256	$x^9$	0	126	0	84	0	36	0	9	0	1
  512	$x^{10}$	252	0	210	0	120	0	45	0	10	0	1
  1024	$x^{11}$	0	462	0	330	0	165	0	55	0	11	0	1